UnicodeEncodeError: "ascii" codec can"t encode character u"\xa0" in position 20: ordinal not in range(128)

Cover Image for UnicodeEncodeError: "ascii" codec can"t encode character u"\xa0" in position 20: ordinal not in range(128)
Matheus Mello
Matheus Mello
published a few days ago. updated a few hours ago

How to Fix the UnicodeEncodeError: 'ascii' codec can't encode character

Have you ever encountered the dreaded UnicodeEncodeError when dealing with unicode characters in your Python code? It can be quite frustrating, especially when the error seems to appear sporadically and is hard to reproduce.

In this blog post, we will address the common issue of UnicodeEncodeError and provide you with easy solutions to fix it consistently. Great news: you don't need to be an expert in Unicode encoding to solve this problem! 😊

Understanding the Problem

The UnicodeEncodeError occurs when you try to encode a Unicode string using the ASCII codec, but the specific character you're trying to encode is not in the range of ASCII characters (i.e., characters with ordinal values less than 128).

In the context of your question, you mentioned that you are using BeautifulSoup to fetch text from different web pages. The error occurs in the following code snippet:

agent_telno = agent.find('div', 'agent_contact_number')
agent_telno = '' if agent_telno is None else agent_telno.contents[0]
p.agent_info = str(agent_contact + ' ' + agent_telno).strip()

The issue arises when trying to concatenate the agent_contact and agent_telno variables, and then convert them to a string. If either of these variables contains a character that is not ASCII-compatible, the UnicodeEncodeError will be raised.

Solutions to Fix the Problem

Now that we understand the problem, let's explore a few solutions to tackle the UnicodeEncodeError consistently:

1. Use Unicode strings throughout your code

By using Unicode strings (prefixed with u) instead of regular strings, Python will automatically handle the encoding for you. Update the code snippet to:

agent_telno = agent.find('div', 'agent_contact_number')
agent_telno = '' if agent_telno is None else agent_telno.contents[0]
p.agent_info = u' '.join([agent_contact, agent_telno]).strip()

This change ensures that the agent_info variable is always a Unicode string.

2. Specify the encoding explicitly

If you know the encoding of the text you're working with, explicitly decode it using the specified encoding. For example, if the encoding is UTF-8, modify the code as follows:

agent_telno = agent.find('div', 'agent_contact_number')
agent_telno = '' if agent_telno is None else agent_telno.contents[0]
p.agent_info = (agent_contact + ' ' + agent_telno).encode('utf-8').strip()

By encoding the string with the appropriate encoding, you can avoid the UnicodeEncodeError.

3. Ignore or replace non-ASCII characters

Depending on your specific use case, you might decide to ignore or replace the non-ASCII characters altogether. You can achieve this by using the errors parameter in the encode method. Here's an example:

agent_telno = agent.find('div', 'agent_contact_number')
agent_telno = '' if agent_telno is None else agent_telno.contents[0]
p.agent_info = (agent_contact + ' ' + agent_telno).encode('ascii', 'ignore').strip()

In this case, the ignore option tells Python to ignore any non-ASCII characters instead of raising an error.

Consistently Fix the Problem

With these solutions in place, you should be able to consistently fix the UnicodeEncodeError when dealing with unicode characters in your code. 🎉

Remember, the solution you choose depends on your specific use case and the requirements of your project. Ensure that you understand the implications of each approach before implementing it in your code.

If you have any other ideas or solutions for this problem, please share them with us in the comments! Let's help each other overcome this challenge together.

Keep coding and embracing the beauty of Unicode! ✨


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